4 ms·
If a pointer/reference escapes the loop you'll have problems whether the thing to the right of the colon is a reference or a copy. If it's a copy, the escaped r
by E6300 10y ago
If a pointer/reference escapes the loop you'll have problems whether the thing to the right of the colon is a reference or a copy. If it's a copy, the escaped reference will definitely be invalid once that iteration complete. If it's a reference, it will remain valid in more situations.