4 ms·
If your data structures have sophisticated invariants, serializing and deserializing them will be painful no matter what, because every invariant becomes one mo
by catnaroek 10y ago
If your data structures have sophisticated invariants, serializing and deserializing them will be painful no matter what, because every invariant becomes one more thing to check after deserializing. And, even if your data structures don't have any invariants, don't you think it would be nice not to have to manually serialize anything? At least it would be nice if the language did this for you automatically.