3 ms·
Re-read the article, bearing in mind that O(sqrt n) is a set that contains O(1).
by DanWaterworth 10y ago
Re-read the article, bearing in mind that O(sqrt n) is a set that contains O(1).
- angry_octet 10y agoYes, but it isn't very helpful to think of it that way, we're not competing to find the weakest constraint.