5 ms·
If they have (A,B,C,D) = (0,1,0,1): A sees 1+0+1 -> guesses (2+0)%4 = 2 (wrong) B sees 0+0+1 -> guesses (1+1)%4 = 2 (wrong) C sees 1+0+1 -> guesses (2+2)%4 =
by pliny 10y ago
If they have (A,B,C,D) = (0,1,0,1):
A sees 1+0+1 -> guesses (2+0)%4 = 2 (wrong)
B sees 0+0+1 -> guesses (1+1)%4 = 2 (wrong)
C sees 1+0+1 -> guesses (2+2)%4 = 0 (wrong)
C sees 0+1+0 -> guesses (1+3)%4 = 0 (wrong)
EDIT: This is twice incorrect, as indicated below.
- im4w1l 10y ago1. You got your signs messed up. They should subtract the observation from the total. 2. C correctly guesses 0 in your example.