3 ms·
Then you're polling the system clock all the time, which is a large unnecessary throughput loss.
by pcwalton 10y ago
Then you're polling the system clock all the time, which is a large unnecessary throughput loss.
- tomp 10y agoBut that's just one instruction, highly paralelisable (I assume), as opposed to going through the kernel... Anyways, I haven't measured it, it's just an idea I had!