3 ms·
epsilon log(r) is the "shielding". I suspect that the field inside will be attenuated by a factor of 1/(epsilon log(r)).
by oneloop 10y ago
epsilon log(r) is the "shielding". I suspect that the field inside will be attenuated by a factor of 1/(epsilon log(r)).
- Panoramix 10y agoepsilon is the gap, so either way it should be on opposite side of the log(r). Smaller gap, stronger shielding but smaller radius weaker shielding. Am I going nuts?
- oneloop 10y agoHm I guess you're right. I don't know what to tell you. I guess we'd have to have a look at the exact definitions they use in the paper :-)