3 ms·

I have been testing this, and I'm not convinced. A lambda with no capture at all (just []) will not compile if it accesses any variable in the scope of the lamb

I have been testing this, and I'm not convinced. A lambda with no capture at all (just []) will not compile if it accesses any variable in the scope of the lambda definition (including globals). I must add [=] or similar to get access to them. What were you referring to? The compiler error is clear: "variable 'lam' cannot be implicitly captured in a lambda with no capture-default specified"

pbsd 10y ago
https://godbolt.org/g/gimahO https://godbolt.org/g/gimahO
- hellofunk 10y ago
  Indeed, I was noticing after my comment that the automatic access of globals is a different behavior than the access to other variables outside the lambda's scope, but not globals. Thanks for the example.