3 ms·
No, it means asymptotically equal to f(n). O(n^2 + n log n) = O(n^2), despite n log n not being a constant.
by lorenzhs 10y ago
No, it means asymptotically equal to f(n). O(n^2 + n log n) = O(n^2), despite n log n not being a constant.
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