> To be clear, yes > (1 - 1) + (1 - 1) + ... != 0 + 0 + ... either I don't see why. I understand the sets themselves are not equal, but the sum of the element

> To be clear, yes > (1 - 1) + (1 - 1) + ... != 0 + 0 + ... either I don't see why. I understand the sets themselves are not equal, but the sum of the elements of those sets is at any given index.