3 ms·
int main(int argl, byte* argb) For having just a byte* stream, not claiming this is a char, when I just have a byte of a char, and without terminating NUL char
by hellcat84 10y ago
int main(int argl, byte* argb)
For having just a byte* stream, not claiming this is a char, when I just have a byte of a char, and without terminating NUL character.