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Are you doing something like this: * Define the series over the 2-adic numbers rather than the reals * Associate every 2-adic integer with its corresponding s
by MichaelBurge 10y ago
Are you doing something like this:
* Define the series over the 2-adic numbers rather than the reals
* Associate every 2-adic integer with its corresponding sequence in the inverse limit Z/2^nZ for n = 1..infinity
* Truncate the sequence to a certain precision(an index i), and make an equivalence class a ~ b if a and b agree on the first i elements. You get a field Z_(2^n), and identities in 2-adic analysis should carry down to the equivalence classes. Here 1 + 2 + 4 ... = -1 in the 2-adics.
That isn't the way I would've thought about signed integers, but it seems like it would work.
- thaumasiotes 10y agoIt's not necessary. Just interpret the bits as coefficients of powers of 2, in a purely conventional manner. Say that leading digits match the high bit rather than being 0 regardless of the high bit. And you're done, you have working signed arithmetic that displays all the behavior you expect and conforms to the geometric series equality. Here 1 + 2 + 4 + ... = -1 in the integers.