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It's not really "lossless" if it only works with a lossy format though, right?
by odbol_ 10y ago
It's not really "lossless" if it only works with a lossy format though, right?
- mark-r 10y agoYes and no. It's not a lossless way to encode an image, but the Lepton step itself doesn't add any loss that wasn't already present in the JPEG to begin with, and it generates a smaller file overall.