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How do we know the inner cryptography isn't weakening the outer cryptography? Couldn't they conflict somehow, making the message easier to decrypt?
by stephengillie 10y ago
How do we know the inner cryptography isn't weakening the outer cryptography? Couldn't they conflict somehow, making the message easier to decrypt?
- Ar-Curunir 10y agoIt because the hash function is just looking at a concatenation of two (computationally) pseudorandom strings, and output the hash of that. If either method is broken (but not both) there is still enough entropy to create a safe key.