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This is demonstrably not true. Suppose I have a pool of 100 candidates, 20% of whom are female. Suppose further that 10% of the pool (8 men, 2 women) meets my "
by phasmantistes 10y ago
This is demonstrably not true. Suppose I have a pool of 100 candidates, 20% of whom are female. Suppose further that 10% of the pool (8 men, 2 women) meets my "bar", and are therefore people that I want to have in my company. But finally suppose that I only have budget for 2 people, not 10.
By your logic, I should hire 2 men, because dividing that candidate pool in half leaves the women at "less than half of a person". Equivalently, I should leave it up to a coin flip, which has an expected value of E(two men).
But why? Since we have already established that the candidates are in all other respects equal, why shouldn't I choose the candidates that I think will do my company the most good: bring in the most diverse perspectives, life experiences, and skill sets?
Of course it is a simplified example. And maybe you think that expressing an interest in diversity in this fashion is "reverse sexism". But I think it is a clear win for my company, a clear win for women everywhere, and I don't care if it isn't a clear win for men -- we win often enough anyway.
- philh 10y ago> Since we have already established that the candidates are in all other respects equal No we haven't. We've established that the candidates are all people you want to hire. That doesn't mean you have no preference between them. It would be really weird if ten candidates all seemed equally competent. And if you can rank them, ~2% of the time there'll be two women at the top, ~36% of the time there'll be a man and a woman, and the rest of the time there'll be two men.