4 ms·
Just from looking at your example here, and not looking at the docs, I'd say that `{x}` and `-> x` both return a function which evaluates `x` and returns the re
by david-given 10y ago
Just from looking at your example here, and not looking at the docs, I'd say that `{x}` and `-> x` both return a function which evaluates `x` and returns the result; so `-> {x}` is equivalent to `{{x}}`, i.e. it returns a function which returns a function which returns `x`.