10 ms·
How about 1/(x * ∞)? Only works if you allow (0 * ∞) = 1, which is admittedly quite shaky.
by nemo1618 10y ago
How about 1/(x * ∞)?
Only works if you allow (0 * ∞) = 1, which is admittedly quite shaky.
- majewsky 10y agoAll arithmetic with +/- ∞ is shaky. But even then, your solution is wrong because it's defined on negative numbers.