4 ms·
After reading the problem but before reading the solution, I came up with 0^ln(x+1). Did I do my math correctly, and is this a legitimate alternative answer?
by d4nte 10y ago
After reading the problem but before reading the solution, I came up with 0^ln(x+1). Did I do my math correctly, and is this a legitimate alternative answer?
- myle 10y agox=0 has the same problem of 0^x being undefined
- jwmerrill 10y agoYes, the results are the same for 0^f(x) where f(x) is any monotonic function with f(0)=0.
- S4M 10y agof has to be monotonic and increasing, and such as f(x) < 0 if x < 0 , and f(x) > 0 if x > 0 (note the strict inequalities, that makes it a condition slightly stronger than monotonic).