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This has been discussed here before: standing people pack tighter than walking people, therefore all standing ends up with more throughput, at the expense of lo
by usrusr 10y ago
This has been discussed here before: standing people pack tighter than walking people, therefore all standing ends up with more throughput, at the expense of lower individual latency (for the would-be walkers).
But you only need that optimization when escalators are at full utilization. In many cities, escalator discipline is low enough that the walk/stand lane pattern deteriorates when the escalator approaches maximum capacity. The minority who don't get it and rudely block the walkers accidentally apply the throughput optimization. London seems to lack a reliable distribution of rude blockers who would accidentally optimize for throughput when necessary, so they need to search for an explicit solution.
- DanBC 10y agoLondon has sufficient loud walkers prepared to yell "Excuse ME!" when blocked.
- cm2187 10y agoAnd not enough of them in my opinion! It is a population where people will endure a lot of things before they lose their courtesy. People eating smelly food, stinking up a whole car. I have even seen some dude getting in a car with a bucket full of fresh fish and no one made any remark. A few angry eyes at most.
- gmluke 10y ago> standing people pack tighter than walking people, therefore all standing ends up with more throughput, at the expense of lower individual latency (for the would-be walkers) If the would-be walkers derive much greater than average utility from a quick journey, isn't it likely that the all-standing regimen achieves higher average throughput at the expense of lower average utility?
- usrusr 10y agoWhen there are enough passengers to saturate full all-standing throughout, reducing throughput to allow individual latency improvement will soon cause waiting times before the bottleneck. Once a sufficiently long queue has formed, newly arriving walkers will not have a quicker total journey than they would have had under throughput optimization with shorter (or no) queues.