3 ms·
The `?` operand appended to function calls makes them behave like `try!()`. It's only in nightly currently, on its way to being stabilized.
by kjaleshire 10y ago
The `?` operand appended to function calls makes them behave like `try!()`. It's only in nightly currently, on its way to being stabilized.
- jeffdavis 10y agoAwesome, I didn't know that got committed! Hopefully stable soon.