3 ms·

How about a copy-able version of the equations so that we can test them to see if they actually work?

by rcfox 17y ago

jackowayed 17y ago
Seconding this. Plus then you can be really nerdy and say "yo, graph this" and send the equation to them and they type it into something and see the message. Usecase: if this had come out like 2 weeks ago with copy-able equations, I probably would have asked someone to prom with it.
jonp 17y ago
The URL of the equation image contains the equation in TeX.
rubidium 17y ago
Copy image location of the img gives you the equation in TeX. Then you can use ToExpression[...] in Mathematica to try and graph it. I haven't tried it myself, but I assume that should work. http://reference.wolfram.com/mathematica/tutorial/GeneratingAndImportingTeX.html http://reference.wolfram.com/mathematica/tutorial/Generating...
- rcfox 17y ago
  Hm, Wolfram|Alpha doesn't like that function, and I don't have access to a real instance of Mathematica...
  - gjm11 17y ago
    Not so good. First minor hurdle: Mma treats backslashes in strings as escapes. But even after doubling them all, I still get "Could not parse [BLAH] as Mathematica input". A bit of experimenting suggests that Mma doesn't like \cdot, so I removed those. I took out the explicit linebreaks at the same time. Now Mma is able to parse the TeX. So far as I can tell from a quick glance, it's understood it OK. Unfortunately, I've had no success in getting it to plot it. RegionPlot[...==0...] produces nothing. ContourPlot[...==0,...] produces nothing. Without the ==0, unsurprisingly, no contour Mma chooses to draw looks at all appropriate. The trouble is that (1) the function is varying so damn fast in the relevant region and (2) those zero contours are all "valley-bottoms", and there's not much way for Mma to know they're there at all. Even giving unreasonably large values for WorkingPrecision,PlotPoints and MaxRecursion doesn't help, unless you consider running the Mathematica kernel out of memory "helping".

How about a copy-able version of the equations so that we can test them to see if they actually work?

by rcfox 17y ago

How about a copy-able version of the equations so that we can test them to see if they actually work?

Seconding this. Plus then you can be really nerdy and say "yo, graph this" and send the equation to them and they type it into something and see the message. Usecase: if this had come out like 2 weeks ago with copy-able equations, I probably would have asked someone to prom with it.

jonp 17y ago

The URL of the equation image contains the equation in TeX.

rubidium 17y ago

Copy image location of the img gives you the equation in TeX. Then you can use ToExpression[...] in Mathematica to try and graph it. I haven't tried it myself, but I assume that should work. http://reference.wolfram.com/mathematica/tutorial/GeneratingAndImportingTeX.html http://reference.wolfram.com/mathematica/tutorial/Generating...

rcfox 17y ago
Hm, Wolfram|Alpha doesn't like that function, and I don't have access to a real instance of Mathematica...
- gjm11 17y ago
  Not so good. First minor hurdle: Mma treats backslashes in strings as escapes. But even after doubling them all, I still get "Could not parse [BLAH] as Mathematica input". A bit of experimenting suggests that Mma doesn't like \cdot, so I removed those. I took out the explicit linebreaks at the same time. Now Mma is able to parse the TeX. So far as I can tell from a quick glance, it's understood it OK. Unfortunately, I've had no success in getting it to plot it. RegionPlot[...==0...] produces nothing. ContourPlot[...==0,...] produces nothing. Without the ==0, unsurprisingly, no contour Mma chooses to draw looks at all appropriate. The trouble is that (1) the function is varying so damn fast in the relevant region and (2) those zero contours are all "valley-bottoms", and there's not much way for Mma to know they're there at all. Even giving unreasonably large values for WorkingPrecision,PlotPoints and MaxRecursion doesn't help, unless you consider running the Mathematica kernel out of memory "helping".