4 ms·

you can use chained map/reduce. object.listOfItems .reduce((item) => item.type === 'car') .map((item) => item.name)); This is way more powerful than xpa

by Chyzwar 10y ago

you can use chained map/reduce. object.listOfItems .reduce((item) => item.type === 'car') .map((item) => item.name)); This is way more powerful than xpath.

mhd 10y ago
Sometimes all you need is printf, not direct memory access to the character byte array.
arethuza 10y ago
What about things like axes in XPath?
AlbertoGP 10y ago
Hi, I think that instead of "reduce((item) => item.type === 'car')" you actually meant "filter((item) => item.type === 'car')".