3 ms·
Can be shortened to let (|>) x f = "%apply" which utilises some language magic and is probably faster.
by LeonidasXIV 10y ago
Can be shortened to
let (|>) x f = "%apply"
which utilises some language magic and is probably faster.
- thedufer 10y agoAt risk of being pedantic, that's actually shorter. It also doesn't work, at least on the version of OCaml I'm familiar with. In order to invoke that particular bit of "language magic", you'd have to declare it external and explicitly give its type: external (|>) : 'a -> ('a -> 'b) -> 'b = "%revapply" Also, `%apply` is usually the `@@` operator. For `|>`, one would expect `%revapply`.