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I'm sorry, but I don't see why/how they would be sent to `map` immediately, given where the parenthesis are in the above code snippet. `Promise.prototype.map`
by jdgiese 10y ago
I'm sorry, but I don't see why/how they would be sent to `map` immediately, given where the parenthesis are in the above code snippet. `Promise.prototype.map` isn't a builtin function is it? If the `map` call was inside the invocation of `Promise.all` then I could see it, but perhaps I am missing something.
- dvlsg 10y agoNo, you're right. That was a mistake on my part. The .map() should be called on the array, as calebegg pointed out.