6 ms·
I think you misunderstood his question. I have the same problem. How do you get from this line: (A1Y and B2Y and B3Y) or (A1Y and A2Y and B3Y) to this
by mh-cx 10y ago
I think you misunderstood his question. I have the same problem.
How do you get from this line:
(A1Y and B2Y and B3Y) or (A1Y and A2Y and B3Y)
to this
(A1Y and B2Y) or (A2Y and B3Y)
BrandonSmithJ just did some replacement to make it easier to read. Maybe he shouldn't have used the same letters to avoid confusion.
Let's write it differently: Why are these terms equivalent?
(u && v && w) || (u && x && w)
(u && v) || (x && w)
- cousin_it 10y agoThey are not equivalent. The former term logically implies the latter term. That means the set of situations described by the former term is a subset of the situations described by the latter term. That means the probability of the former set should be less or equal than the probability of the latter set.