4 ms·
What if the odd's of disarming the guy are 95%?
by ErrantX 17y ago
What if the odd's of disarming the guy are 95%?
- yummyfajitas 17y agoP( fight | takes wallet ) = 50%. P( no injury | fight ) = 95%. P( injury | hand over wallet ) = P(injury | fight) P(fight | hand over wallet) = 0.05 x 0.5 = 0.025 So P(no injury | hand over wallet) = 97.5%.
- ErrantX 17y agogood point :) However it makes a slight assumption that you still have 95% chance of winning if you hand over the wallet and are then attacked. This is probably not the case as the attacker gains a reasonable advantage by being first (maybe only 2 or 3% in this case) I also assumed the 50% was referring to the percentage chance of being actually harmed rather than having to fight. In which case your stats do break down.