3 ms·
40 m/s is a velocity, not an acceleration (deceleration). I guess that you mean 40 m/s^2
by tigershark 11y ago
40 m/s is a velocity, not an acceleration (deceleration). I guess that you mean 40 m/s^2
- dkbrk 11y agoHe did say total deceleration, so I believe he meant the landing burn starts at a velocity of 40 m/s and consequently the total ΔV of the landing burn is 40 m/s. That said, I have no idea where he got that number, whether 40 m/s or 40 m/s^2; both are incorrect. The best estimate available for the flight dynamics can be found at flightclub.io, specifically for JCSAT-14: https://flightclub.io/results/?id=eeaf889e-f3d8-4f9b-be98-b75ea987e8d2&code=JC14 https://flightclub.io/results/?id=eeaf889e-f3d8-4f9b-be98-b7... This shows the landing burn starting at a velocity of 269 m/s and experiencing a peak deceleration of 12.3g = 121 m/s^2 I don't know how accurate these numbers are, but some fans put quite a bit of effort into getting the flightclub.io profiles as close to reality as possible, so they tend to be pretty good.
- gpm 11y agoOops, you are right, I did miss a ^2. The approximation I had is almost certainly less reliable than flightclubs, not sure why it was so low, will have to look at the math I did and figure out what I screwed up.