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It goes against the Linux kernel documentation, yes. As has been pointed out to them, it doesn't go against the documentation on OS X or any of the BSDs. But th
by cwyers 11y ago
It goes against the Linux kernel documentation, yes. As has been pointed out to them, it doesn't go against the documentation on OS X or any of the BSDs. But they engage in the same behavior on those systems.
- lmm 11y agoWell, perfectly reasonable to take the intersection of capabilities rather than special-case each platform. AIUI the behaviour of /dev/urandom and /dev/random is the same on OSX and *BSD, so there's no problem with their behaviour there.