3 ms·
No. If Weight is Satoshi, he knows who Satoshi is, so those are not orthogonal. Basically, the first dimension has four discrete states, while the second has tw
by IgorPartola 11y ago
No. If Weight is Satoshi, he knows who Satoshi is, so those are not orthogonal. Basically, the first dimension has four discrete states, while the second has two.
- tanderson92 11y agoThank you for posting this method of analysis (as well as the poster who pointed to ACH). I think the analytically-minded typically think along these lines, but it is very helpful to me to have a system to formalize around.