3 ms·
The whole tank? Or did you mean it can make a teeny tiny hole all the way straight through it?
by beamatronic 11y ago
The whole tank? Or did you mean it can make a teeny tiny hole all the way straight through it?
- the8472 11y agoNow that I looked it up, the analogy used was "could melt half a ton of copper". So it's less than your average car. Still a lot of energy to get rid off at short notice, in case of emergency shutdowns. If I recall correctly they modulate the beam with steering magnets so it sweeps through an area and water-cool the target material. And its absorption can't be too high so the energy gets deposited over some depth. Or from wikipedia: > Each of the two beam dumps, in case, for instance, of a dipole magnet quench, must be able to dissipate 362 MJ of beam energy in the 90 μs circulation time, which equates to a power of 4 TW.