3 ms·
I'm not really sure what the argument here is. Given the fact that each vertex of the die has 10 triangles that sum to 595, and including a non-malicious roll
by dsp1234 11y ago
I'm not really sure what the argument here is.
Given the fact that each vertex of the die has 10 triangles that sum to 595, and including a non-malicious roll against a backdrop, I don't see how this die is any more or less fair than a normal d6 (which I believe we can concede is 'fair'). After all, if you want to cheat at dice, then you can cheat at dice regardless of any common understanding of 'fairness'.
In particular, I was responding to the following comment, "If its too large, it may only reach a portion of the neighboring values at each bounce".
My argument was only that if you drop the dice from say a distance of 3", and it doesn't bounce then at a minimum, you wouldn't get a large grouping of numbers that are all near each other (Even if you were able to somehow pick a specific 'vertex' to always land up, you're going to have a total average of 59.5). In other words, you couldn't drop the die such that you could guarantee a range of 110-120 (which you could for example do on a MTG spindown die, which is fair but not uniform). In other words, even if there is no bounce, a typical rolling of the dice would be 'good enough' for say a pen and paper RPG, and even just dropping it without the bounce is likely enough to give non-Vegas levels of 'fairness' even if 'it may only reach a portion of the neighboring values at each bounce'.
- logicallee 11y agomathematically, if your "range" is one of the ten numbers 108, 43, 21, 18, 32, 40, 79, 50, 94, 59 then it is just as broken as if your "range" is 110-120. it's not considered fair. fair means random and evenly distributed. (when it comes to dice and coins.)
- laxatives 11y agoThat enforces that the mean value should be close to 60, but doens't say much about whether it is fair in that it should have also have a uniform distribution.