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I don't know what you're taking issue with. The results of sorting in JS with a simple (a<b) comparison will necessarily vary by JS implementation, and I'm sugg

• CJefferson 11y ago
  I am refering to this: In (almost) every other language ever the following is true. In Javascript it is false. [2] < [11] This means: [[2], [11]].sort() // Javascript: [ [11], [2] ]
  • fenomas 11y ago
    You're overlapping a couple of separate things. The article and my initial comment were about sorting arrays of numbers. If you're sorting arrays of arrays, the behavior of ([2] < [11]) is slightly beside the point, since Array.sort() doesn't compare the arrays, it converts all elements to strings first. As for the actual behavior of ([2] < [11]), the issue there is that "Array" is not a type in JS, arrays are just objects that happen to have properties called "0" and "1" and so on. Hence operators don't have any special cases for arrays, so getting comparisons to work like you had hoped would mean the comparison operator would need weird special rules where, whenever it's passed two objects it checks if they both have properties called "0", and if so do one thing, if not do something else, etc.