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What about the energy dissipated by collision with the interstellar medium? Won't that slow the probe considerably? Apologies for significant errors and apprec
by ridgeguy 11y ago
What about the energy dissipated by collision with the interstellar medium? Won't that slow the probe considerably?
Apologies for significant errors and appreciation for corrections in the following hasty and unchecked calcs.
Wikipedia [1] says the ISM density ranges from as little as 1e-4/cm^3 for hot, ionized regions to 1e6/cm^3 for cool, dense regions.
Let's say it's all neutral hydrogen, which conveniently masses 1g/mole. A mole is 6.02e23 particles. A single H atom masses about 1.66e-27kg. And let's say the ISM has a hydrogen atom density kind of midway between the extremes: 10/cm^3 (=1e7/m^3).
Let's say the spacecraft presents 2.54cm x 2.54cm (1 square inch) = 6.45e-4 m^2 to the ISM as it moves. I think this is small compared with what the project is proposing, but we can scale as needed.
At 20% of C, the spacecraft sweeps out a volume of [(3e8.2)m/sec](6.45e-4m^2) = about 3.9e4m^3 every second, which contains about 3.9e11 hydrogen atoms, or a mass of about
6e-16kg/sec.
If all those atoms hit and stick to the spacecraft, they all get accelerated to the spacecraft's velocity. At 20%C, relativistic mass increase should be small, so let's ignore it. The energy needed to accelerate one hydrogen atom to 20%C is about 3e12J/atom.
If the spacecraft is hitting 3.9e11 atoms/sec and spending 3e-12J/atom accelerating impacting atoms to 20%C, that's slightly over 1 Watt that's decelerating the spacecraft.
Over a 20-year trip (6.31e8 seconds and assuming no deceleration), that's 6.31e8 W-sec, or 631 megaJoules of energy needed to sustain 20%C because of collisions with the interstellar medium.
A Watt isn't much, but over a 20 year trip, it integrates to a pretty big energy requirement, or a significant deceleration of an unpowered, very low mass spacecraft.
It looks to me like small, light probes won't maintain their high initial velocity very long into the cruise phase without ongoing propulsion.
[1] https://en.wikipedia.org/wiki/Interstellar_medium https://en.wikipedia.org/wiki/Interstellar_medium
- igravious 11y agoSo you're saying they'll slow down significantly due to the friction of the interstellar medium so they'll need some form of propulsion of their own?
- ridgeguy 11y agoYes, but yk's note that the friction load is a small fraction of the craft's kinetic energy makes me rethink whether the effect will matter much.
- yk 11y agoWell a 1 g spacecraft at .2 c has roughly 10^12 J kinetic energy, so it just loses something in the order of 10^-3 of its energy due to collisions with the ISM. (Which should have an order of magnitude less density in the solar neighborhood.)
- eduren 11y agoGood point. On their website, they list the specific challenges that they need to address, including a page for "4 Photon Thrusters". Would those be able to counteract the deceleration? http://breakthroughinitiatives.org/Challenges/3 http://breakthroughinitiatives.org/Challenges/3
- ridgeguy 11y agoPerhaps they might. Looking forward to reading the entire project description when I get home this evening.
- DavidSJ 11y ago> about 3.9e4m^3 every second, which contains about 3.9e11 hydrogen atoms I think this step is off by 1e5. It contains 3.9e16 hydrogen atoms at 1e6/cm^3. So that 631 MJ becomes 63.1 TJ.
- ridgeguy 11y agoI assumed an interstellar medium density of 10 H atoms/cm^3, which is 1e7 atoms/m^3, given 1e6 cm^3 per m^3. I think the volume swept out by the spacecraft is about right: (3e8m/sec)(.2)6.45e-4m^2 is about 3.9e4m^3/sec. Then, 1e7 H atoms/m^3 * 3.9e4m^3/sec gives about 3.9e11 atoms/sec hitting the (1 inch square) spacecraft.
- DavidSJ 11y agoI see, I missed the part where you assume 10 atoms per cm^3.