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Schrodinger's equation doesn't even include special relativistic effects. It's not exact (at least not if you mean it exactly describes nature in general). Neit
by smaddox 11y ago
Schrodinger's equation doesn't even include special relativistic effects. It's not exact (at least not if you mean it exactly describes nature in general). Neither is Dirac's equation; it includes special relativistic effects for a single particle, but not general relativistic effects or multi-particle interactions (at least as far as I understand it).
- wyager 11y agoThe general form using the unspecified Hamiltonian operator is compatible with relativity.