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You didn't read my post. I said O(2^N) which means basically computationally intractable for large N and even if Moore's law were to continue indefinitely it
by narrator 11y ago
You didn't read my post. I said O(2^N) which means basically computationally intractable for large N and even if Moore's law were to continue indefinitely it would still be computationally intractable for large N. O(N^2) problems, on the other hand, are far more approachable by software.