4 ms·

Wildcards are not variables. Wildcards don't get expanded in quotes. Variables get expanded in double quotes but not single quotes. $@ obeys all the same expans

• kazinator 11y ago
  > $@ obeys all the same rules as all other variables. That's hardy the case. Most other variables do not represent the positional parameters, and don't have the logic of "$@" which effectively produces "$1" "$2" "$3" ...
  • adrusi 11y ago
    I was refering to the expansion behavior, which was the point in contention. I've clarified the original comment.
• hibbelig 11y ago
  No, $@ is special where $* is regular. Consider the following script foo.sh and call it like so: ./foo.sh one "a b" two The $* part will print one line, the $@ part will print three lines. #!/bin/bash for x in "$*"; do echo $x done for x in "$@"; do echo $x done I use "$@" often, but to this day I don't fully understand how $@ works...
  • kazinator 11y ago
    Unquoted $@ works exactly like unquoted $* . Quoted "$* " separates the parameters using the first character stored in IFS, or with nothing if IFS is unset/null. Usually, the first character of IFS is space, giving the impression that "$* " means "separate with spaces"; i.e. that it's just an ordinary quote job around $* (i.e. that it is "regular", in your words). Quoted "$@" does ... what you clearly understand.