3 ms·

Yes, it is. But x isn't one of the operands -- it's a list of all the operands. And (and) should evaluate to #t for the same reason as (+) should evaluate to 0

by gjm11 11y ago

Yes, it is. But x isn't one of the operands -- it's a list of all the operands. And (and) should evaluate to #t for the same reason as (+) should evaluate to 0 and (*) should evaluate to 1. (And also why 0! = 1.)

S4M 11y ago
Ha got it, thanks! But what's e then?
- kazinator 11y ago
  The environment object which eval needs to resolve variable references. This operator is defining a function which interprets and operator calls.