> You made one small mistake at the end Oh yes, so I did. Sorry about that. > What did you ask wolfram alpha to get the -log m + 1 - 1/m? This, I think: http

> You made one small mistake at the end Oh yes, so I did. Sorry about that. > What did you ask wolfram alpha to get the -log m + 1 - 1/m? This, I think: http://www.wolframalpha.com/input/?i=Integrate[m+t^%28m-1%29+Log[m+t^%28m-1%29],{t,0,1} http://www.wolframalpha.com/input/?i=Integrate[m+t^%28m-1%29...] I get a message about computation time exceeded, but I also get the answer (both the indefinite integral and the definite). I don't have a subscription.