3 ms·
Smallest positive m such that 77 divides m^2+7m+89 is greatly simplified by realizing (mod 77) m^2+7m+89=m^2+7m+12=(m+3)(m+4).
by octonion 11y ago
Smallest positive m such that 77 divides m^2+7m+89 is greatly simplified by realizing (mod 77) m^2+7m+89=m^2+7m+12=(m+3)(m+4).
- baddox 11y agoThat's precisely how the article explains it.
- imaginenore 11y agoRead the article.
- vanattab 11y ago<nitpick> m^2+7m+89 != m^2+7m+12 (m^2+7m+89)%77 =(m^2+7m+12)%77 </nitpick>