4 ms·
No, because the distributedness of the representation means that exponentially large Markov chains would be needed to replace linearly growing deep models. See
by curuinor 11y ago
No, because the distributedness of the representation means that exponentially large Markov chains would be needed to replace linearly growing deep models. See this paper on the recurrent temporal RBM (http://www.cs.utoronto.ca/~ilya/pubs/2008/rtrbm.pdf http://www.cs.utoronto.ca/~ilya/pubs/2008/rtrbm.pdf).
It's like saying, "aren't binary trees just linked lists?"