> But you cannot do the reverse: you cannot make a type from a foreign package conform to your interface by adding new methods to it. I thought you could. You

> But you cannot do the reverse: you cannot make a type from a foreign package conform to your interface by adding new methods to it. I thought you could. You don't add the methods directly to it, but you can easily embed the foreign type into a new type that confirms to the interface you want. type FooWrapper struct { Foo } func (fw FooWrapper) SomeFunc() { ... }