2 ms·

It's being assigned a pointer-to-void, yes?

• derefr 11y ago
  It is, yes, according to the typespec of memcpy(3). But according to the standard, it shouldn't be; it should be returning a [whatever-type-src-was-passed-in-as]. I have doubt that there's any way in C to specify variable return type like that—but the C standard, AFAIK, doesn't require that memcpy(3)—or anything else from libc—be implementable in C. It can be, as Lisp would put it, a "special form." To get an implicit pointer-to-char-typed buffer out of memcpy(3), you should have to attach the malloc(3)-returned buffer to a pointer-to-char-typed variable (or give it an explicit cast) to give it a type, and then pass it in as dest.