4 ms·
That's a remarkably close guess. A small non-zero curvature would correspond to a non-zero cosmological constant, which is precisely what seems to be driving t
by contravariant 11y ago
That's a remarkably close guess.
A small non-zero curvature would correspond to a non-zero cosmological constant, which is precisely what seems to be driving the accelerated expansion of the universe (there are other explanations but this is the simplest one).