Whilst that is true, it really all depends on the resistance of the thing that you are passing the current through. Remember that P = I^2 R (i.e. power goes as

Whilst that is true, it really all depends on the resistance of the thing that you are passing the current through. Remember that P = I^2 R (i.e. power goes as the square of the current for a constant resistance) so for an object of constant resistance then to double the current than you need 4 times the power.