3 ms·

> photons are gauge bosons and thus are automatically their own antiparticle So is W^+, but it is charged, hence not its own antiparticle. W^- should in this c

> photons are gauge bosons and thus are automatically their own antiparticle So is W^+, but it is charged, hence not its own antiparticle. W^- should in this case be considered the antiparticle.

cygx 11y ago
And before electroweak symmetry breaking?
- dukwon 11y ago
  Before EWSB you have four massless bosons: W+, W−, W0 and B0 The W0 and B0 mix to give the photon and Z0 The W+, W− and Z0 gain mass and the photon is left massless