3 ms·
Quick and Dirty(probably better ways to do it): def permute(string, prefix = ''): if len(string) == 1: print prefix + string return
by bshep 17y ago
Quick and Dirty(probably better ways to do it):
def permute(string, prefix = ''):
if len(string) == 1:
print prefix + string
return
for x in range(0, len(string)):
new_prefix = prefix + string[x]
unused_chars = string[0:x] + string[x+1:]
permute(unused_chars, new_prefix)