3 ms·
Kind of, but it's a chain. It works by shifting bits through all flip-flops until they've all "dropped out" of an I/O pin. So you don't need any expensive muxes
by nhaehnle 11y ago
Kind of, but it's a chain. It works by shifting bits through all flip-flops until they've all "dropped out" of an I/O pin. So you don't need any expensive muxes or crossbars.
It's actually one of the largest and most realistic real-world application of TSP and related problems.