3 ms·

The article says not to do this: uint32_t numbers[64]; memset(numbers, 0, sizeof(numbers) * 64); That is certainly true because that is a buffer overrun.

• jacquesgt 11y ago
  Which is a perfect example of why their approach is better. Less arithmetic to get right with their approach.
  • minitech 11y ago
    To be fair, the correct version isn’t very arithmeticky. memset(numbers, 0, sizeof numbers);