3 ms·
Given that p(A and B) = p(B and A) p(A and B ) = p(A) * p(B|A) we have: p(A) * p(B|A) = p(B) * p(A|B) p(B|A) = p(B) * p(A|B) / p(A)
by sorokod 11y ago
Given that
p(A and B) = p(B and A)
p(A and B ) = p(A) * p(B|A)
we have:
p(A) * p(B|A) = p(B) * p(A|B)
p(B|A) = p(B) * p(A|B) / p(A)