4 ms·
It's a matter of definition. It's perfectly consistent to say Haskell does not allow side-effects as they stop being such once they have been reified.
by cygx 11y ago
It's a matter of definition. It's perfectly consistent to say Haskell does not allow side-effects as they stop being such once they have been reified.
- tome 11y agoBut then it's equally consistent to say that C doesn't allow side-effects because the whole program is reified.