2 ms·
"There is no API to pass a filename" Use: convertToString(filename, sourceStr); and pass sourceStr. You are right about how much boilerplate there is - thou
by bainsfather 11y ago
"There is no API to pass a filename"
Use:
convertToString(filename, sourceStr);
and pass sourceStr.
You are right about how much boilerplate there is - though you can hide it a bit with helper fns and a few macros.